Calculation of the preset level of the valve:
Two-pipe heating system
Example of calculation:
Solution to: level of presetting
Given:
- heat output: Q = 960 W
- cooling of water: t1 - t2 = 15 K (70/55 °C)
- pressure loss of radiator with valve: Δp = 65 mbar
- heat capacity of water: c = 1,163 Wh/kg.K
Solution: weight flow:
| m = | Q c . (t1 - t2) | = | 960 1,163 . 15 | = 55 kg/h |
Level of presetting (see diagram): 3
Level 3 presetting
| Ventil Kompakt Radiators without connecting fittings | Level of valve presetting | Highest allowed oper. temperature [°C] | Highest allowed oper. working pressure [bar] | |||||||
|---|---|---|---|---|---|---|---|---|---|---|
| 1 | 2 | 3 | 4 | 5 | 6 | |||||
| Valve with presetting at six levels and with thermostatic head | kV [m³/h] |
min ÷ max |
0,025 ÷ 0,047 |
>0,047 ÷ 0,126 |
>0,126 ÷ 0,269 |
>0,269 ÷ 0,417 |
>0,417 ÷ 0,600 |
>0,600 ÷ 0,840 |
110 | 10 |
| kVS [m³/h] |
0,051 | 0,133 | 0,294 | 0,430 | 0,630 | 0,980 | ||||