Pressure losses of convectors

Pressure losses of convectors

KORAFLEX FK 9/16, FK 11/16, KORABASE 10

KORAFLEX FK 9/20, 9/28, 11/20, 11/28, KORALINE 9/18 a 9/24, KORABASE 20, KORAFLEX FV 8/28, 9/28,11/28, KORAFLEX FV InPool 13/34

KORAFLEX FK 9/34 a 11/34, KORAFLEX FV 11/34, KORABASE 30

KORAFLEX FK  9/42, 11/42, KORAFLEX FV 11/42

KORAFLEX FK 15/28, 19/28, 30/28, 45/28, KORABASE 22

KORAFLEX FK  15/34, 19/34, 30/42, 45/42, KORABASE 33

KORAFLEX FK 15/42, 19/42

KORAWALL WK 45/6, 60/6

KORAWALL WK  45/12, 60/12

KORAWALL WI 45/11

KORAFLEX FV 11/20, KORAFLEX FI 11/20

KORAFLEX FI 13/34

KORAFLEX FW 13/34

Examples of conversion to a variant temperature difference

Δt = (tw1 + tw2) / 2 – ti

Where: 

tw1 is the inlet water temperature (°C) 
tw2 is the outlet water temperature (°C)
ti 
   is the air temperature (°C)
Δt  
is the cooling of water (K)

The resistance coefficient is valid for both 1/2'' connections. You will find the kt factor in the table of correction factors of the particular element.


Entered: 

  • KORABASE 22/140 heating element
  • Rated operating condition: 75/65/20 °C
  • Qn = 1198 W should be converted to the temperature difference Δt = 40 K
  • Q = Qn × factor kt = 1198 × 0,748 = 896 W

Entered: 

  • KORAWALL WK 140/60/6 heating element
  • Rated operating condition: 75/65/20 °C
  • Qn = 1018 W should be converted to the temperature difference Δt = 30 K
  • Q = Qn × factor kt = 1018 × 0,515 = 525 W

 

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